Assume for this problem that the company has 5 Buicks and 4 Hondas, and two cars are selected randomly and given to sales representatives?
What is the probability of both cars being Buicks, given that both are of the same make?
5/9 * 4/8
Number of ways to select 2 cars from 5 Buicks = 5C2 = (5*4)/(1*2) = 10
Number of ways to select 2 cars from 4 Hondas = 4C2 = (4*3)/(1*2) = 6
We're given that both cars selected are the SAME MAKE, so they were either both Buicks or both Hondas, making a total of 16 possible pairs from which they could have come.
Therefore probability that both were Buicks = 10/16 = 5/8
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